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Thread: Finding the vertex of the parabolic graph

  1. October 27th 2008, 05:38 PM #1
    epetrik
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    Angry Finding the vertex of the parabolic graph

    Please help me!
    I need to find the vertex of the parabolic graph of the following equation
    y=9(x-2)^2+5

    Where do I begin?
    Distributing?
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  2. October 27th 2008, 05:57 PM #2
    skeeter
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    Quote Originally Posted by epetrik View Post
    Please help me!
    I need to find the vertex of the parabolic graph of the following equation
    y=9(x-2)^2+5

    Where do I begin?
    Distributing?
    the quadratic y = a(x - h)^2 + k has its vertex at coordinates (h,k)
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  3. October 28th 2008, 01:52 PM #3
    epetrik
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    Still confused...

    Ok..but where do I go from there? Does that mean my vertex (-2,5)
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  4. October 28th 2008, 02:15 PM #4
    skeeter
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    Quote Originally Posted by epetrik View Post
    Ok..but where do I go from there? Does that mean my vertex (-2,5)
    vertex at (2,5)
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