# Thread: Finding the vertex of the parabolic graph

1. ## Finding the vertex of the parabolic graph

I need to find the vertex of the parabolic graph of the following equation
y=9(x-2)^2+5

Where do I begin?
Distributing?

2. Originally Posted by epetrik
I need to find the vertex of the parabolic graph of the following equation
y=9(x-2)^2+5

Where do I begin?
Distributing?
the quadratic $y = a(x - h)^2 + k$ has its vertex at coordinates $(h,k)$

3. ## Still confused...

Ok..but where do I go from there? Does that mean my vertex (-2,5)

4. Originally Posted by epetrik
Ok..but where do I go from there? Does that mean my vertex (-2,5)
vertex at (2,5)