Please help me! I need to find the vertex of the parabolic graph of the following equation y=9(x-2)^2+5 Where do I begin? Distributing?
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Originally Posted by epetrik Please help me! I need to find the vertex of the parabolic graph of the following equation y=9(x-2)^2+5 Where do I begin? Distributing? the quadratic $\displaystyle y = a(x - h)^2 + k$ has its vertex at coordinates $\displaystyle (h,k)$
Ok..but where do I go from there? Does that mean my vertex (-2,5)
Originally Posted by epetrik Ok..but where do I go from there? Does that mean my vertex (-2,5) vertex at (2,5)
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