Finding the vertex of the parabolic graph

• October 27th 2008, 06:38 PM
epetrik
Finding the vertex of the parabolic graph
I need to find the vertex of the parabolic graph of the following equation
y=9(x-2)^2+5

Where do I begin?
Distributing?
• October 27th 2008, 06:57 PM
skeeter
Quote:

Originally Posted by epetrik
I need to find the vertex of the parabolic graph of the following equation
y=9(x-2)^2+5

Where do I begin?
Distributing?

the quadratic $y = a(x - h)^2 + k$ has its vertex at coordinates $(h,k)$
• October 28th 2008, 02:52 PM
epetrik
Still confused...
Ok..but where do I go from there? Does that mean my vertex (-2,5)
• October 28th 2008, 03:15 PM
skeeter
Quote:

Originally Posted by epetrik
Ok..but where do I go from there? Does that mean my vertex (-2,5)

vertex at (2,5)