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Thread: need help please :)

  1. #1
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    Oct 2008
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    6

    need help please :)

    What are the zeros of y-7=4x^2

    and Solve square root of 2x^2 - sqaure root of 2 = 0
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  2. #2
    Member
    Joined
    Oct 2008
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    $\displaystyle y-7 = 4x^2$
    $\displaystyle -7 = 4x^2$
    Never true in the reals.
    $\displaystyle \sqrt(2x^2) - \sqrt(2) =0$
    $\displaystyle (\sqrt(2x^2)-\sqrt(2))(\sqrt(2x^2)+\sqrt(2)) =0$
    $\displaystyle 2x^2 -2 =0$
    $\displaystyle x^2 -1 = 0$
    $\displaystyle x = -1 \, or\, 1$
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