There is no reason to include -2 and 3 in the list of critical points. especially when it's not defined
The conditions for a point to be critical are :
- derivative = 0. << x=1 is the only solution
- or undefined for the derivative but defined for the function itself. << the domain of the function is . At x=0, the derivative is not defined. So you can see for that.
The boundaries can intervene in the absolute extremas list, but not really in the critical points list.
For the extremas, you have to check that any point in the interval is < or > to the extrema.
(not sure, but you can check it )2)
Found that the critical number was
Given interval [-1,6]
I need help finding the absolute extremas here even though its just plugging in
Suppose to plug it into this original function:
See if for any value of x,