Solve for x: logbx = (3/2)logb4-(2/3)logb8+2logb2
Apply various rules of logarithms to get all the terms on the right side of the equation in one logarithm.
$\displaystyle \log_bx=\log_b(8)-\log_b(4)+\log_b(4)\implies\log_bx=\log_b(?)$
I leave it for you to fill in the ?.
Then x = ?.
Can you take it from here?
--Chris
w00t!! my 12th post!!!