# Solve for x

• October 25th 2008, 01:37 PM
dc52789
Solve for x
Solve for x: logbx = (3/2)logb4-(2/3)logb8+2logb2
• October 25th 2008, 01:40 PM
Chris L T521
Quote:

Originally Posted by dc52789
Solve for x: logbx = (3/2)logb4-(2/3)logb8+2logb2

Apply various rules of logarithms to get all the terms on the right side of the equation in one logarithm.

$\log_bx=\log_b(8)-\log_b(4)+\log_b(4)\implies\log_bx=\log_b(?)$

I leave it for you to fill in the ?.

Then x = ?.

Can you take it from here?

--Chris

w00t!! my 12(Sun)(Sun)th post!!! (Party)
• October 25th 2008, 02:17 PM
dc52789
Quote:

Originally Posted by Chris L T521
Apply various rules of logarithms to get all the terms on the right side of the equation in one logarithm.

$\log_bx=\log_b(8)-\log_b(4)+\log_b(4)\implies\log_bx=\log_b(?)$

I leave it for you to fill in the ?.

Then x = ?.

Can you take it from here?

--Chris

w00t!! my 12(Sun)(Sun)th post!!! (Party)

so...is the answer x = 8?
• October 25th 2008, 02:25 PM
Shyam
yes, x = 8
• October 25th 2008, 02:26 PM
dc52789
Quote:

Originally Posted by Shyam
yes, x = 8

sweet ^^