Find point or points on the graph where the tangent line is horizontal. f(x) = 6x^2+2x-7 h(s) = x^3-2x^2+4x-9
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$\displaystyle f'(x) = 0 $ and $\displaystyle h'(s) = 0 $ and solve, this is because the slope at the horizantal is equal to zero always.
Originally Posted by rod789 Find point or points on the graph where the tangent line is horizontal. f(x) = 6x^2+2x-7 h(s) = x^3-2x^2+4x-9 Which graph? You give two functions. And surely you mean h(x), not h(s).
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