Need help on this one.

If the percent of adult height attained by a 5 to 15 year old girl can be modeled by f(x) 62+35log10(x-4), where x is the age in years and f(x) is the percent. At age 14, what percent of her adult height has a girl reached?

Please show me the steps so I won't get confused.

Quote:

---

Originally Posted by dc52789

If the percent of adult height attained by a 5 to 15 year old girl can be modeled by f(x) 62+35log10(x-4), where x is the age in years and f(x) is the percent. At age 14, what percent of her adult height has a girl reached?

Please show me the steps so I won't get confused.

---

$\displaystyle f(x)=62+35 \log(x-4)$

$\displaystyle f(14)=62+35 \log(14-4)$

$\displaystyle f(14)=62+35 \log(10)$

$\displaystyle f(14)=62+35(1)$

$\displaystyle f(14)=97$