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Math Help - Little challenge for persons who know Calculus and Geometry

  1. #1
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    Little challenge for persons who know Calculus and Geometry

    I've found hard to answer this problem, I would apreciate your help:

    Find the points on the graph of f(x) = 1/3x^3+x^2-x-1 at which the slope is (a) -1, (b) 2, and (c) 0
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  2. #2
    Rhymes with Orange Chris L T521's Avatar
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    Quote Originally Posted by yasu7 View Post
    I've found hard to answer this problem, I would apreciate your help:

    Find the points on the graph of f(x) = 1/3x^3+x^2-x-1 at which the slope is (a) -1, (b) 2, and (c) 0
    Find f'(x):

    f'(x)=x^2+2x-1

    Now find x when f'(x)=-1, f'(x)=2 and f'(x)=0

    --Chris
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  3. #3
    Junior Member toraj58's Avatar
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    for example for f'(x) = 0 the solution is like this:

    x^2+2x-1=0
    X^2+2x+1-2=0
    (x+1)^2-2=0
    (x+1)^2=2
    Then answers are:
    x = -1+\sqrt2
    or
    x= -1-\sqrt2
    Last edited by toraj58; October 24th 2008 at 01:09 PM.
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