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Math Help - Inverse function of this one...

  1. #1
    Newbie petike's Avatar
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    Question Inverse function of this one...

    Hi,
    does anybody know how to find out the "inverse" function of this function:

    <br />
f(x) = 3 + \arcsin (2x + 1)<br />

    I have absolutely no idea how to start.
    Any help is welcome.

    Thanks.
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  2. #2
    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by petike View Post
    Hi,
    does anybody know how to find out the "inverse" function of this function:

    <br />
f(x) = 3 + \arcsin (2x + 1)<br />

    I have absolutely no idea how to start.
    Any help is welcome.

    Thanks.
    no surprises here. as always, to find the inverse function, switch x and y and solve for y
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  3. #3
    Newbie petike's Avatar
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    Unhappy But what then?

    Quote Originally Posted by Jhevon View Post
    no surprises here. as always, to find the inverse function, switch x and y and solve for y
    Ok, so I know how to start.
    But what then. I know I should make y alone. But how?
    I would like to see the whole process of that.

    Thanks anyway.
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  4. #4
    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by petike View Post
    Ok, so I know how to start.
    But what then. I know I should make y alone. But how?
    I would like to see the whole process of that.

    Thanks anyway.
    note that if \theta = \arcsin \varphi, then \sin \theta = \varphi

    now can you try?
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  5. #5
    Newbie petike's Avatar
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    Thumbs up Thanks

    Quote Originally Posted by Jhevon View Post
    note that if \theta = \arcsin \varphi, then \sin \theta = \varphi

    now can you try?
    Ah, thanks,
    now it's clearer.

    You've got my thanks.
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