Given that A is the point (0,11), B is the point (8,5) and O is the origin , calculate
How to find the,
a) the coordinates of M , the mid point of AB,
b) the gradient of OM,
c) the lenght of the line AB,
d) the equation of the line AB
Given that A is the point (0,11), B is the point (8,5) and O is the origin , calculate
How to find the,
a) the coordinates of M , the mid point of AB,
b) the gradient of OM,
c) the lenght of the line AB,
d) the equation of the line AB
From the average of the x coordinate and y coordinates.
(8+0)/2=4 and (11+5)/2=8. Thus, the point is (4,8).
Same as the slope of AB because it is part of the same line.b) the gradient of OM,
Thus, (11-5)/(0-8)=(-6)/(-8)=3/4
Use the distance formula,c) the lenght of the line AB,
(0-8)^2+(11-5)^2=8^2+6^2=64+36=100
But that is the square of the distance. Take the square root,
10
The y-intercept is 11 because you have (0,11) and x=0 at that point.d) the equation of the line AB
Thus, the equation is,
y=(3/4)x+11