Results 1 to 4 of 4

Math Help - natural log question

  1. #1
    Newbie
    Joined
    Sep 2008
    Posts
    10

    natural log question

    e^x - 6e^(-x) = 1
    solve for x

    I think you can make 1=lne or e^0 and that helps but i'm still having trouble at the next step.
    Follow Math Help Forum on Facebook and Google+

  2. #2
    Junior Member
    Joined
    Oct 2008
    From
    Guernsey
    Posts
    69
    If you multiply through by e^x you should end up with an equation you can solve
    Follow Math Help Forum on Facebook and Google+

  3. #3
    Super Member
    Joined
    Jun 2008
    Posts
    792
    Multiply both sides by e^x to get:

    e^{2x} - 6 = e^x

    Rearrange it into a quadratic:

    e^{2x} - e^x - 6 = 0

    Notice that this factors into:

    (e^x-3)(e^x+2)=0

    Can you continue?
    Follow Math Help Forum on Facebook and Google+

  4. #4
    Newbie
    Joined
    Sep 2008
    Posts
    10
    got it, thanks alot guys!
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Natural domain question
    Posted in the Pre-Calculus Forum
    Replies: 2
    Last Post: March 31st 2011, 04:22 AM
  2. Natural Log and Log Assignment Question
    Posted in the Algebra Forum
    Replies: 2
    Last Post: May 26th 2009, 12:47 PM
  3. Natural Log Question
    Posted in the Pre-Calculus Forum
    Replies: 2
    Last Post: September 26th 2008, 09:56 PM
  4. Weird natural log question
    Posted in the Calculus Forum
    Replies: 1
    Last Post: August 21st 2008, 05:51 PM
  5. Natural logarithm question
    Posted in the Calculus Forum
    Replies: 3
    Last Post: March 30th 2008, 01:42 PM

Search Tags


/mathhelpforum @mathhelpforum