Thread: natural log question

e^x - 6e^(-x) = 1
solve for x

I think you can make 1=lne or e^0 and that helps but i'm still having trouble at the next step.

If you multiply through by e^x you should end up with an equation you can solve

Multiply both sides by e^x to get:



Rearrange it into a quadratic:



Notice that this factors into:



Can you continue?

got it, thanks alot guys!