e^x - 6e^(-x) = 1 solve for x I think you can make 1=lne or e^0 and that helps but i'm still having trouble at the next step.
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If you multiply through by e^x you should end up with an equation you can solve
Multiply both sides by e^x to get: Rearrange it into a quadratic: Notice that this factors into: Can you continue?
got it, thanks alot guys!
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