This is my last item in my assignment and all I know is the vertical asymptote. Can you guys help me with this problem.
Given f(x) = x^3 +8 / x +2
Find the asymptotes and holes of the graph. Find the x and Y axis.
Thanks in advance.
The rational function in its original state is not defined at x=-2 because that would cause the denominator to be 0.
After Earboth simplified the function to , x=-2 is now ok. If it were still undefined at x=-2, you would have a vertical asymptote at x = -2. But that's not the case. Therefore, you have a hole in the curve where x=-2. The corresponding y coordinate is found by using your simplified function and seeing that f(-2) = 12. This function has 'point discontinuity' at (-2, 12)