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how to input Log(base)2 (x) into TI83 plus Thank you!

Quote: Originally Posted by mak15 how to input Log(base)2 (x) into TI83 plus Thank you! It can be done via change of base formula: $\displaystyle \log_ax=\frac{\ln x}{\ln a}$ Thus, $\displaystyle \log_2 x=\frac{\ln x}{\ln 2}$ $\displaystyle \frac{\ln x}{\ln 2}$ is what you would put in the calculator. --Chris