1. ## Inverse Functions

this is on the Barron's SAT Math IIC Book page 41.

Which of the following equations can represent the inverse of the attachment? (the line on the attachment is y=f(x)

a) y=-2x+1
b) y=2x+1
c) 1/2x+1
d) y=1/2x-1
e) y=1/2x-(1/2)

I know that inverse means that for example the inverse of function y=2x is y=x/2 but how do you do this problem?

2. Originally Posted by fabxx
this is on the Barron's SAT Math IIC Book page 41.

Which of the following equations can represent the inverse of the attachment? (the line on the attachment is y=f(x)

a) y=-2x+1
b) y=2x+1
c) 1/2x+1
d) y=1/2x-1
e) y=1/2x-(1/2)

I know that inverse means that for example the inverse of function y=2x is y=x/2 but how do you do this problem?

The equation of the line in the attachment is y = x + 1 (do you know how to get this equation?). Can you find the inverse of this?

(None of the options are correct for the image you've attached, by the way).

3. how did you get the equation for the graph? cuz the in the book it said that the function has a f(x) function

4. Originally Posted by fabxx
how did you get the equation for the graph? cuz the in the book it said that the function has a f(x) function

from the graph, we see that the line passes through the points (-1,0) and (0,1). from this we can find the slope, and then we can find the equation of the line.

there seems to be a lot of mistakes in this problem set that you are doing. there have been several questions now where none of the responses are correct. i suggest you find another source to practice from

5. another way to guess the equation is like this:

the equation is in this form: y= mx + b

where m is slope and because it is parallel with y=x then m = 1

also b is Y-intercept and from digaram is 1

so y= x + 1

6. Originally Posted by Jhevon
from the graph, we see that the line passes through the points (-1,0) and (1,0).
Typo! The line passes through (-1, 0) and (0, 1).

from this we can find the slope, and then we can find the equation of the line.

there seems to be a lot of mistakes in this problem set that you are doing. there have been several questions now where none of the responses are correct. i suggest you find another source to practice from

7. Originally Posted by HallsofIvy
Typo! The line passes through (-1, 0) and (0, 1).
yes, thanks. i'll fix it