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Math Help - Inverse Functions

  1. #1
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    Inverse Functions

    this is on the Barron's SAT Math IIC Book page 41.

    Which of the following equations can represent the inverse of the attachment? (the line on the attachment is y=f(x)

    a) y=-2x+1
    b) y=2x+1
    c) 1/2x+1
    d) y=1/2x-1
    e) y=1/2x-(1/2)

    I know that inverse means that for example the inverse of function y=2x is y=x/2 but how do you do this problem?

    Thanks in advance
    Attached Thumbnails Attached Thumbnails Inverse Functions-barrons.jpg  
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  2. #2
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    Quote Originally Posted by fabxx View Post
    this is on the Barron's SAT Math IIC Book page 41.

    Which of the following equations can represent the inverse of the attachment? (the line on the attachment is y=f(x)

    a) y=-2x+1
    b) y=2x+1
    c) 1/2x+1
    d) y=1/2x-1
    e) y=1/2x-(1/2)

    I know that inverse means that for example the inverse of function y=2x is y=x/2 but how do you do this problem?

    Thanks in advance
    The equation of the line in the attachment is y = x + 1 (do you know how to get this equation?). Can you find the inverse of this?

    (None of the options are correct for the image you've attached, by the way).
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  3. #3
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    how did you get the equation for the graph? cuz the in the book it said that the function has a f(x) function

    Thanks in advance!!
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  4. #4
    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by fabxx View Post
    how did you get the equation for the graph? cuz the in the book it said that the function has a f(x) function

    Thanks in advance!!
    from the graph, we see that the line passes through the points (-1,0) and (0,1). from this we can find the slope, and then we can find the equation of the line.

    there seems to be a lot of mistakes in this problem set that you are doing. there have been several questions now where none of the responses are correct. i suggest you find another source to practice from
    Last edited by Jhevon; October 26th 2008 at 09:48 AM. Reason: thanks, HallsofIvy
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  5. #5
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    another way to guess the equation is like this:

    the equation is in this form: y= mx + b

    where m is slope and because it is parallel with y=x then m = 1

    also b is Y-intercept and from digaram is 1

    so y= x + 1
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  6. #6
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    Quote Originally Posted by Jhevon View Post
    from the graph, we see that the line passes through the points (-1,0) and (1,0).
    Typo! The line passes through (-1, 0) and (0, 1).

    from this we can find the slope, and then we can find the equation of the line.

    there seems to be a lot of mistakes in this problem set that you are doing. there have been several questions now where none of the responses are correct. i suggest you find another source to practice from
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  7. #7
    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by HallsofIvy View Post
    Typo! The line passes through (-1, 0) and (0, 1).
    yes, thanks. i'll fix it
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