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Thread: Difference quotient

  1. October 20th 2008, 06:43 PM #1
    Heather10
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    Difference quotient

    ok so i have a big test tomorrow and i don't understand how to do this type of problem...

    f(x)=x^2-x+1, (f(2+h)-f(2))/(H)
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  2. October 20th 2008, 07:24 PM #2
    11rdc11
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    Quote Originally Posted by Heather10 View Post
    ok so i have a big test tomorrow and i don't understand how to do this type of problem...

    f(x)=x^2-x+1, (f(2+h)-f(2))/(h)

    f(x)=x^2-x+1

    \lim_{h \to 0}~\frac{(2+h)^2 - (2+h) +1 -[(2)^2 -2 +1]}{h}

    \lim_{h \to 0}~\frac{4 + 4h + h^2 -2 -h +1 -4 + 2 -1}{h}

    \lim_{h \to 0}~\frac{h^2+4h}{h}
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