Practice Find the equation in general form of the circle with the given properties. Center at (-3, 4); r = 5√5
Follow Math Help Forum on Facebook and Google+
The general equation for a circle is: $\displaystyle (x-a)^2+(y-b)^2=r^2$ Where (a,b) is the centre of the circle and r is the radius. Just plug and play!
so I got the answer: x^2+y^2+6x-8y-109=0 It counted it incorrect, what did I do wrong?
You're almost there! I get a different constant (ie not -109).
Im confused...cause aren't you supposed to subtract the 125 from -16? or I must be adding or subtracting something wrong right... I got -125? does that sound better?
View Tag Cloud