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Math Help - Velocity problem

  1. #1
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    Question Velocity problem

    A ball is hit straight up from a height of 4 ft with an initial velocity of 65 ft/sec. Find the maximum height of the ball and the number of seconds to reach that height.

    Thank you in advance for any help!
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  2. #2
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    Initial velocity of ball u = 65 \;\;ft/s

    acceleration due to gravity, g = -9.81 \;\;m/s^2(acting downwards)

    at maximum height, the ball stops for a moment, and then returns back down.
    so, final velocity, v= 0
    suppose it takes time t to reach maximum height.

    v=u+gt

    <br />
0=65-9.81t

    t= \frac{65}{9.81}=6.6

    it takes 6.6 s to reach max height.

    Maximum height reached, h is given by

    h=ut + \frac{1}{2}gt^2

    h=(65)(6.6) + \frac{1}{2}(-9.81)(6.6)^2

    h=215.34\;\; ft

    total height from ground = 4 + 215.34 = 219.34 ft
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  3. #3
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    Smile thanks so much

    Thank you so much for your help!!
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