(x-2)^2+(y+3)^2=25

Printable View

- Sep 12th 2006, 11:51 AMstephaniejsketch the graph
(x-2)^2+(y+3)^2=25

- Sep 12th 2006, 11:56 AMCaptainBlack
- Sep 12th 2006, 02:12 PMQuick
I have posted the graph below for you to see. (It may look like an oval, but it's a circle)

Cap'nBlack (or anyone else), what is the trick to see where the center is, and the size of the radius? my best guess is that given an equation in the form:**$\displaystyle (x+a)^2+(y+b)^2=c$**the radius is**$\displaystyle \sqrt c$**and the center point is**$\displaystyle (-a,-b)$** - Sep 12th 2006, 11:39 PMGlaysher