# sketch the graph

• Sep 12th 2006, 11:51 AM
stephaniej
sketch the graph
(x-2)^2+(y+3)^2=25
• Sep 12th 2006, 11:56 AM
CaptainBlack
Quote:

Originally Posted by stephaniej
(x-2)^2+(y+3)^2=25

This is a circle of radius 5 with centre at (2,-3)

RonL
• Sep 12th 2006, 02:12 PM
Quick
I have posted the graph below for you to see. (It may look like an oval, but it's a circle)

Cap'nBlack (or anyone else), what is the trick to see where the center is, and the size of the radius? my best guess is that given an equation in the form: $(x+a)^2+(y+b)^2=c$ the radius is $\sqrt c$ and the center point is $(-a,-b)$
• Sep 12th 2006, 11:39 PM
Glaysher
Quote:

Originally Posted by Quick
I have posted the graph below for you to see. (It may look like an oval, but it's a circle)

Cap'nBlack (or anyone else), what is the trick to see where the center is, and the size of the radius? my best guess is that given an equation in the form: $(x+a)^2+(y+b)^2=c$ the radius is $\sqrt c$ and the center point is $(-a,-b)$

That is correct