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Math Help - Problem with Complex numbers.

  1. #1
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    Problem with Complex numbers.

    I have (z^(3))+2i=0 and the second is (z^(2))-2i.z-2i=1 Pls show me the right direction with these problems,10x
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    Quote Originally Posted by wiesmann View Post
    I have (z^(3))+2i=0 and the second is (z^(2))-2i.z-2i=1 Pls show me the right direction with these problems,10x
    z^3 = -2i => z = the three cube roots of -2i. Have you been taught how to find the three cube roots of a complex number using de Moivre's Theorem?

    z^2 - 2i z - 2i = 1 => (z - i)^2 = 2i. Therefore z - i = the two square roots of 2i. Have you been taught how to find the two square roots of a complex number using de Moivre's theorem?
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    Quote Originally Posted by mr fantastic View Post
    z^3 = -2i => z = the three cube roots of -2i. Have you been taught how to find the three cube roots of a complex number using de Moivre's Theorem?

    z^2 - 2i z - 2i = 1 => (z - i)^2 = 2i. Therefore z - i = the two square roots of 2i. Have you been taught how to find the two square roots of a complex number using de Moivre's theorem?
    OK thanks i see it now
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