solve for k.
1b). Put the value of k in the equation
and solve for
2). initial number of cells
final number of cells
doubling time d = 4 min
total time, t = ?
t = 48 min
b) number of bacteria after t = 1 hour = 60 min (when vial is full)
number of bacteria when vial is full = 32768.
number of bacteria when vial is half-full
time t = ?
t = 56 min
the vial is half full after 5:56 am
c) the vial is full after one hour, i e, at 6:00 am