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Math Help - Exponential Functions

  1. #1
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    Exponential Functions

    Theres 3 questions that I dont get...Please help!! Thanks

    1)An xray beam of intensity, I0, in passing through absorbing material x millimeters thick merges with an intensity, I, given by I = I0e^-kx. when the material is 9 millimeters thick 50% of the intensity lost.(I0 = initial amount)

    a) calculate the value of the constant k to the three decimal places.
    b) What percentage intensity, to one decimal place, remains if the material is 20 millimeters thick?

    2) A lab technician placed a baterial cell intovial at 5 a.m. the cells divide in such a way that the number of ells doubles every 4 minutes. the vial is full one hour later.
    a) how long does it take for the cells to divide to 4096?
    b)at what time is the vial half full?
    c) at what time is the vial full?

    3)Determine the pH, tothe nearest tenth, of an acidic solution whose [OH-] concentration is 3.98x10^-10 mol/L if [H+][OH-]=1.0 x 10^-14. If the ph of a solution is defined as pH=-log(h+)?

    MANY THANKS
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  2. #2
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    1a). use, \frac{I}{I_0}=e^{-9k}

    \frac{50}{100}=e^{-9k}

    \frac{1}{2}=e^{-9k}

    solve for k.

    1b). Put the value of k in the equation

    \frac{I}{I_0}=e^{-20k}

    and solve for \frac{I}{I_0}

    2). initial number of cells A_0 = 1

    final number of cells A_n=4096

    doubling time d = 4 min

    total time, t = ?

    a) use, A_n = A_0 \left(2 \right)^{\frac{t}{d}}

    4096= 1\left(2 \right)^{\frac{t}{4}}

    2^{12}= \left(2 \right)^{\frac{t}{4}}

    12=\frac{t}{4}

    t = 48 min

    b) number of bacteria after t = 1 hour = 60 min (when vial is full)

    A_n = A_0 \left(2 \right)^{\frac{t}{d}}

    A_n = 1 \left(2 \right)^{\frac{60}{4}}

    A_n = \left(2 \right)^{15}

    A_n = 32768

    number of bacteria when vial is full = 32768.

    number of bacteria when vial is half-full A_n= \frac{32768}{2} = 16384

    time t = ?

    A_n = A_0\left(2 \right)^{\frac{t}{d}}

    16384 = 1\left(2 \right)^{\frac{t}{4}}

    2^{14} = \left(2 \right)^{\frac{t}{4}}

    t = 56 min

    the vial is half full after 5:56 am

    c) the vial is full after one hour, i e, at 6:00 am
    Last edited by Shyam; October 16th 2008 at 08:59 PM.
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  3. #3
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    Thx..
    i still need help with 2 b c and 3 =(
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  4. #4
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    Quote Originally Posted by T3chnoBoi View Post
    Thx..
    i still need help with 2 b c and 3 =(
    which part you did not get in 2 b c ??
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  5. #5
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    at waht time is the vial half full....
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