Originally Posted by
earboth I assume that the paraboloid has an opening of 4'' and a depth of 3''. If so:
The cross-section of the paraboloid through the focus and the vertex of the paraboloid must be a parabola. Use a coordinate system where the vertex is V(0, 0) and the point P(3, 2) are located on the parabola.
The general equation of a parabola opening to the right is:
$\displaystyle y^2 = 2p\cdot x$
Use the coordinates of P to calculate p. (I've got $\displaystyle p = \frac23$)
Then the focus F is the point where all parallel light rays will be concentrated. F has the coordinates $\displaystyle F\left(\frac p2\ ,\ 0\right)$