Results 1 to 4 of 4

Math Help - Evaluate 5e^3ln6

  1. #1
    Newbie
    Joined
    Sep 2008
    Posts
    2

    Evaluate 5e^3ln6

    i know it's pretty simple to solve - but i can't find anything in my book about it and i know i have a test tomorrow over it any help?
    Follow Math Help Forum on Facebook and Google+

  2. #2
    Member
    Joined
    Oct 2008
    Posts
    147
    Break it down to simpler forms. You know e^ln(x) = x so try to make something of that form.
    5e^3(ln(6))= 5e^(ln(6^3)). Move the in front of the ln to be the power of the 6.
    Then we know that e^ln(x) = x, so
    5e^(ln(6^3)) = 5 (6^3) = 5(27)(64) = 320(27) = (300+20)(27) = 8100+ 540 = 8640.
    Follow Math Help Forum on Facebook and Google+

  3. #3
    Newbie
    Joined
    Sep 2008
    Posts
    2
    i figured it out and i'm glad for the help but that's the wrong answer. you were close.

    the way i did it to find the answer(i have the answer sheet so it helps a lot)

    is this
    5e^3ln6
    5e^ln6^3
    5e^ln216 6^3 = 216 - i think that's where u got it wrong

    e and ln cancel out
    5 * 216 = 1080

    again thanks for the help, i might be posting some other stuff in this area later tonight - midterms etc...
    Follow Math Help Forum on Facebook and Google+

  4. #4
    Member
    Joined
    Oct 2008
    Posts
    147
    I fail at arithmetic, I did 12^3 by accident, it should have been 5(27)(8) instead of 64.
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Evaluate
    Posted in the Trigonometry Forum
    Replies: 1
    Last Post: May 17th 2010, 11:28 AM
  2. evaluate
    Posted in the Calculus Forum
    Replies: 3
    Last Post: May 15th 2010, 05:05 PM
  3. Evaluate
    Posted in the Calculus Forum
    Replies: 10
    Last Post: January 14th 2010, 05:49 AM
  4. Evaluate the sum
    Posted in the Algebra Forum
    Replies: 3
    Last Post: October 26th 2009, 04:45 PM
  5. Evaluate the following
    Posted in the Calculus Forum
    Replies: 3
    Last Post: October 24th 2009, 06:56 PM

Search Tags


/mathhelpforum @mathhelpforum