# Thread: on the slope of line

1. ## on the slope of line

Practice Write the equation of the line that passes through the given point and is perpendicular to the given line. Write the answer in slope-intercept form.
P(-3, 3), y + 9x = -15

i did the whole y-y1=mx(x-x1)
and i came up with y-3=-1/9x[x-(-3)]
= y-3=-1/9(x+3)
=9y-27=-x-3
=9y=-1/9x+8/3

2. What am I doing wrong?
$y + 9x = -15$

$y = -9x - 15$

the slope of this line is $m = -9$. the perpendicular slope is $\frac{1}{9}$

using the slope $m = \frac{1}{9}$ and the point $(-3, 3)$ ...

$y - 3 = \frac{1}{9}(x + 3)$

$y - 3 = \frac{1}{9}x + \frac{1}{3}$

$y = \frac{1}{9}x + \frac{10}{3}$