What am I doing wrong?
the slope of this line is . the perpendicular slope is
using the slope and the point ...
Practice Write the equation of the line that passes through the given point and is perpendicular to the given line. Write the answer in slope-intercept form.
P(-3, 3), y + 9x = -15
i did the whole y-y1=mx(x-x1)
and i came up with y-3=-1/9x[x-(-3)]
= y-3=-1/9(x+3)
=9y-27=-x-3
=9y=-1/9x+8/3
What am I doing wrong? PLEASE HELP