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Math Help - Simple logarithm problem.

  1. #1
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    Co. Waterford, Ireland
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    Simple logarithm problem.

    Hi there,

    If I have something like

    I = n*exp(-d/(m*cos(theta))
    where n, d, and m are constants.

    and I try to solve for d.

    I take the natural logarithm of both sides.

    But I'm confused about the RHS.

    Do I take the n outside the natural logarithm?

    As in n*ln(exp(-d/(m*cos(theta))



    Thanks.
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  2. #2
    Rhymes with Orange Chris L T521's Avatar
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    Santa Cruz, CA
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    Quote Originally Posted by waynex View Post
    Hi there,

    If I have something like

    I = n*exp(-d/(m*cos(theta))
    where n, d, and m are constants.

    and I try to solve for d.

    I take the natural logarithm of both sides.

    But I'm confused about the RHS.

    Do I take the n outside the natural logarithm?

    As in n*ln(exp(-d/(m*cos(theta))



    Thanks.
    If you're approaching it this way, note that \ln(ab)=\ln a+\ln b

    So, \ln(n\cdot\exp(-d/(m\cos(\theta))=\ln n + \ln(\exp(-d/(m\cos(\theta))

    Can you take it from here?

    --Chris
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  3. #3
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    Co. Waterford, Ireland
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    Yes that's fine, thanks for your help!
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