1. ## Simple logarithm problem.

Hi there,

If I have something like

$I = n*exp(-d/(m*cos(theta))$
where n, d, and m are constants.

and I try to solve for d.

I take the natural logarithm of both sides.

But I'm confused about the RHS.

Do I take the n outside the natural logarithm?

As in $n*ln(exp(-d/(m*cos(theta))$

Thanks.

2. Originally Posted by waynex
Hi there,

If I have something like

$I = n*exp(-d/(m*cos(theta))$
where n, d, and m are constants.

and I try to solve for d.

I take the natural logarithm of both sides.

But I'm confused about the RHS.

Do I take the n outside the natural logarithm?

As in $n*ln(exp(-d/(m*cos(theta))$

Thanks.
If you're approaching it this way, note that $\ln(ab)=\ln a+\ln b$

So, $\ln(n\cdot\exp(-d/(m\cos(\theta))=\ln n + \ln(\exp(-d/(m\cos(\theta))$

Can you take it from here?

--Chris

3. Yes that's fine, thanks for your help!