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Math Help - Need Help Graphing

  1. #1
    Newbie
    Joined
    Oct 2008
    Posts
    6

    Need Help Graphing

    I need to graph the function: Find and show on the graph, the vertex, y-intercept, x-intercept if any, the axis of symmetry. I think I have the answers. I just don't no how to graph it. I believe it's a parabola. The function is f(x)=2x2+4x-30
    My answers :
    Vertex-1,-32)
    y-intercept0,-30)
    x-intercept-5,3)
    axis of symmetry:-1
    Domain:All Real Numbers
    Range:[-2,infinity)

    Thanks,
    Freedom100
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  2. #2
    Junior Member
    Joined
    Mar 2008
    Posts
    49
    Hello

    It is a parabola

    If you need to draw the graph by hand then you can make a table of values for x and y.

    \begin {tabular}{c c c c c c c c c c c c}<br />
x & -6 & -5 & -4 & -3 & -2 & -1 & 0 & 1 & 2 & 3 & 4 \\<br />
y & 18 & &-14&-24& & &-30& & & 0<br />
\end {tabular}<br />

    Complete the table by substituting the values of x in to, y = 2x^2+4x-30 and then plot the points.
    Or use graphing software, if you are 'allowed'.

    Check your x - intercepts, there are two. The values of x when y = 0. They are both in your table.
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