I've been going through a textbook and I've came across Simultaneous equations by this point. I can do many, such as:

c = 7d - 2 [1]

3c - 4d = 11 [2]

To do this I subbed c in [2] and did this method:

3(7d-2) - 4d = 11

21d - 4d - 6 = 11

17d = 17

d = 1

And then went back to 3c - 4d = 11

I found that 3c = 15

andc = 5.

However the last question is:

6x - 5y = 27

3y = 1 - 5x

Now I'm pretty sure you don't use the same method as last time so what can I do here