How do I find f^-1 (2), x for f^-1 (x) = 0 I have a graph with a function f on it, f(x) = [ 2x^3 + 1/2 x + 5 ]/2 And also, it would be great if someone could find the equation for the inverse of f(x)
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Originally Posted by realintegerz How do I find f^-1 (2), x for f^-1 (x) = 0 I have a graph with a function f on it, f(x) = [ 2x^3 + 1/2 x + 5 ]/2 And also, it would be great if someone could find the equation for the inverse of f(x) Remember that for inverses the domain and range switch. For example has domain A and range B than has domain B and range A Ok so using this info we can solve what and is since we know the function is 1) is so 2)To solve the other problem set and solve for x
hmmm.. im stuck on that f^-1 (2)... So far i simplified it to... -2 = 4x^3 + x
Originally Posted by realintegerz hmmm.. im stuck on that f^-1 (2)... So far i simplified it to... -2 = 4x^3 + x i tried using the rational root theorem but couldn't get any nice roots so i used the cubic equation. You could also do it numerically.
Originally Posted by 11rdc11 i tried using the rational root theorem but couldn't get any nice roots so i used the cubic equation. You could also do it numerically. I know the quadratic equation..but not cubic... could you explain that?
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