How do I find f^-1 (2), x for f^-1 (x) = 0
I have a graph with a function f on it,
f(x) = [ 2x^3 + 1/2 x + 5 ]/2
And also, it would be great if someone could find the equation for the inverse of f(x)
Remember that for inverses the domain and range switch. For example
$\displaystyle f(x)$ has domain A and range B than $\displaystyle f^{-1}(x)$ has domain B and range A
Ok so using this info we can solve what $\displaystyle f^{-1}(x) = 0$ and $\displaystyle f^{-1}(2)$ is since we know the function is
$\displaystyle f(x) = \frac{2x^3 +\frac{x}{2} +5}{2}$
1) $\displaystyle f^{-1}(x) = 0$ is $\displaystyle f(0)=?$
so
$\displaystyle x = \frac{5}{2}$
2)To solve the other problem set
$\displaystyle 2 = \frac{2x^3 +\frac{x}{2} +5}{2}$
and solve for x