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Math Help - the equation of a straight line is 3x+2y=11. find the equation of a parrallel line pa

  1. #1
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    the equation of a straight line is 3x+2y=11. find the equation of a parrallel line pa

    i made it y=-3/2 x +11.5

    but i think its wrong help
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  2. #2
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    Quote Originally Posted by coyoteflare View Post
    i made it y=-3/2 x +11.5

    but i think its wrong help
    3x+2y=11

    Transpose (move) the 3x to the right side of the equation, thus changing its sign.

    2y=-3x+11

    Divide each term by 2

    y=-\frac{3}{2}x+\frac{11}{2}
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  3. #3
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    Quote Originally Posted by masters View Post
    3x+2y=11

    Transpose (move) the 3x to the right side of the equation, thus changing its sign.

    2y=-3x+11

    Divide each term by 2

    y=-\frac{3}{2}x+\frac{11}{2}
    but surely you have to substitute 5,4 in somewhere?
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  4. #4
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    Quote Originally Posted by coyoteflare View Post
    but surely you have to substitute 5,4 in somewhere?
    I'm sorry. I'm not seeing the rest of your question.....

    Are you trying to find the equation of a line through (5,4) that is parallel to y=-\frac{3}{2}x+\frac{11}{2}?
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  5. #5
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    yeh thats what im after [:
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  6. #6
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    If that be the case, then we will use the same slope as:

    y=-\frac{3}{2}x+\frac{11}{2} which is -\frac{3}{2}

    We need to find the y-intercept. Use the slope-intercept form of the linear equation and use the point given (5, 4).

    y=mx+b

    4=-\frac{3}{2}(5)+b

    4=-\frac{15}{2}+b

    \frac{23}{2}=b

    Substituting back into y=mx+b, we have

    y=-\frac{3}{2}x+\frac{23}{2}

    And your answer was right!!
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