the equation of a straight line is 3x+2y=11. find the equation of a parrallel line pa

**coyoteflare** · October 13th 2008, 10:00 AM

i made it y=-3/2 x +11.5

but i think its wrong help

**masters** · October 13th 2008, 10:04 AM

Originally Posted by coyoteflare

i made it y=-3/2 x +11.5

but i think its wrong help

$3x+2y=11$

Transpose (move) the 3x to the right side of the equation, thus changing its sign.

$2y=-3x+11$

Divide each term by 2

$y=-\frac{3}{2}x+\frac{11}{2}$

**coyoteflare** · October 13th 2008, 10:06 AM

Originally Posted by masters

$3x+2y=11$

Transpose (move) the 3x to the right side of the equation, thus changing its sign.

$2y=-3x+11$

Divide each term by 2

$y=-\frac{3}{2}x+\frac{11}{2}$

but surely you have to substitute 5,4 in somewhere?

**masters** · October 13th 2008, 10:10 AM

Originally Posted by coyoteflare

but surely you have to substitute 5,4 in somewhere?

I'm sorry. I'm not seeing the rest of your question.....

Are you trying to find the equation of a line through (5,4) that is parallel to $y=-\frac{3}{2}x+\frac{11}{2}$ ?

**coyoteflare** · October 13th 2008, 10:11 AM

yeh

thats what im after [:

**masters** · October 13th 2008, 10:16 AM

If that be the case, then we will use the same slope as:

$y=-\frac{3}{2}x+\frac{11}{2}$ which is $-\frac{3}{2}$

We need to find the y-intercept. Use the slope-intercept form of the linear equation and use the point given (5, 4).

$y=mx+b$

$4=-\frac{3}{2}(5)+b$

$4=-\frac{15}{2}+b$

$\frac{23}{2}=b$

Substituting back into y=mx+b, we have

$y=-\frac{3}{2}x+\frac{23}{2}$

And your answer was right!!

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