1. ## lines in graph

Ok , so i have another question, now i dunno how to graph linear equations lol grade 9 stuff.

So i dunno how to graph these follow questions
4y-27-x = 0
3x-12= 7y + 28
So am i suppose to convert into another form, or how do i plot this on a graph please?

2. Originally Posted by lickman
Ok , so i have another question, now i dunno how to graph linear equations lol grade 9 stuff.

So i dunno how to graph these follow questions
4y-27-x = 0
3x-12= 7y + 28
So am i suppose to convert into another form, or how do i plot this on a graph please?
to graph straight lines, you only need two points. the x and y-intercepts are usually the easiest points to find, especially if the line is already in the slope-intercept form. so find the two points, and plot them on the the axis, and then draw a straight line through them, and you're done

there are better threads you can search for, as this topic has been discussed numerous times, but after a quick search, i found this. see if it helps

3. so is the x and y intercept for equation one is : y= int 4 and x= int -1 ? lol i am slow forgetting all my fundamentals sry for the inconvenient, cause i know slope form is y = mx + b? is that it lol ?

4. Originally Posted by lickman
so is the x and y intercept for equation one is : y= int 4 and x= int -1 ? lol i am slow forgetting all my fundamentals sry for the inconvenient, cause i know slope form is y = mx + b? is that it lol ?
yes, that is the slope intercept form. you can bring them to that form if it makes your life easier. but basically, to find the x-intercept, set y = 0 and solve for x, to find the y-intercept, set x = 0 and solve for y

5. can u show me on to do one step by step I"M SWRY
4y -27 - x = 0

6. Originally Posted by lickman
can u show me on to do one step by step I"M SWRY
4y -27 - x = 0
set x = 0, then 4y - 27 = 0 which means y = 27/4

thus the y-intercept is (0,27/4)

set y = 0, then -27 - x = 0 which means x = -27

thus the x-intercept is (-27,0)

now plot those two points on your axis, and draw a straight line through them. see below

now do the other one

7. Originally Posted by Jhevon
set x = 0, then 4y - 27 = 0 which means y = 27/4

thus the y-intercept is (0,27/4)

set y = 0, then -27 - x = 0 which means x = -27

thus the x-intercept is (-27,0)

now plot those two points on your axis, and draw a straight line through them. see below

now do the other one
the person that is asking this... if you don't get how they got... -27,0 for the x intercept..
when you have -27- x = 0
when you bring over the -27 it will look like -x = 27 ...
than you can't have the x as a negative so you divide both by -1, and it becomes a negative again...

and when the x or y intercept is 0, it is automatically on the line... and for the y intercept.. to graph it you go up 27 over 4 because it is in a fraction.