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Math Help - lines in graph

  1. #1
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    lines in graph

    Ok , so i have another question, now i dunno how to graph linear equations lol grade 9 stuff.

    So i dunno how to graph these follow questions
    4y-27-x = 0
    3x-12= 7y + 28
    So am i suppose to convert into another form, or how do i plot this on a graph please?
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  2. #2
    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by lickman View Post
    Ok , so i have another question, now i dunno how to graph linear equations lol grade 9 stuff.

    So i dunno how to graph these follow questions
    4y-27-x = 0
    3x-12= 7y + 28
    So am i suppose to convert into another form, or how do i plot this on a graph please?
    to graph straight lines, you only need two points. the x and y-intercepts are usually the easiest points to find, especially if the line is already in the slope-intercept form. so find the two points, and plot them on the the axis, and then draw a straight line through them, and you're done

    there are better threads you can search for, as this topic has been discussed numerous times, but after a quick search, i found this. see if it helps
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  3. #3
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    so is the x and y intercept for equation one is : y= int 4 and x= int -1 ? lol i am slow forgetting all my fundamentals sry for the inconvenient, cause i know slope form is y = mx + b? is that it lol ?
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  4. #4
    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by lickman View Post
    so is the x and y intercept for equation one is : y= int 4 and x= int -1 ? lol i am slow forgetting all my fundamentals sry for the inconvenient, cause i know slope form is y = mx + b? is that it lol ?
    yes, that is the slope intercept form. you can bring them to that form if it makes your life easier. but basically, to find the x-intercept, set y = 0 and solve for x, to find the y-intercept, set x = 0 and solve for y
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  5. #5
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    can u show me on to do one step by step I"M SWRY
    4y -27 - x = 0
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  6. #6
    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by lickman View Post
    can u show me on to do one step by step I"M SWRY
    4y -27 - x = 0
    set x = 0, then 4y - 27 = 0 which means y = 27/4

    thus the y-intercept is (0,27/4)

    set y = 0, then -27 - x = 0 which means x = -27

    thus the x-intercept is (-27,0)

    now plot those two points on your axis, and draw a straight line through them. see below


    now do the other one
    Attached Thumbnails Attached Thumbnails lines in graph-line.jpeg  
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  7. #7
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    Quote Originally Posted by Jhevon View Post
    set x = 0, then 4y - 27 = 0 which means y = 27/4

    thus the y-intercept is (0,27/4)

    set y = 0, then -27 - x = 0 which means x = -27

    thus the x-intercept is (-27,0)

    now plot those two points on your axis, and draw a straight line through them. see below


    now do the other one
    the person that is asking this... if you don't get how they got... -27,0 for the x intercept..
    when you have -27- x = 0
    when you bring over the -27 it will look like -x = 27 ...
    than you can't have the x as a negative so you divide both by -1, and it becomes a negative again...

    and when the x or y intercept is 0, it is automatically on the line... and for the y intercept.. to graph it you go up 27 over 4 because it is in a fraction.
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