Ugh! Circle problems
1) Find an equation with center on the line y =3x and tangent to y-axis with coordinates (0,2).
2) Find an equation for the tangent of a circle (x-3)^2 + (y+2)^2 = 13 on the points (0, -4).
3) Find an equation for the circle that passes through the points (0,0), (4,1), (3,-3).
I have no idea how to do these! Any hints would be helpful on how to start these problems :)
If these were posted separately, as in one question per thread, I could help you more.
Originally Posted by NeedHelp18
Since you only need hints, maybe no use to separate them anyway. (But it will be better if you post questions one each per thread.)
1) The tangent line along the y-axis is perpendicular to a radius of the circle. So the center of the circle has a y-coordinate of 2.
2) Do it by the popular method: get dy/dx, etc.
Or, if you're not into Calculus yet, the slope of the tangent line is the trig function tangent value of the angle made by the tangent line with the x-axis.
See if you can find, using this way, that m = -3/2 for the said tangent line.
3) A standard form of the equation of a circle whose center is at (a,b) and whore radius is r, is
(x-a)^2 +(y-b)^2 = r^2
You have 3 given points on the circle, ... you have 3 unknowns, ... so?
um i still dont understand (Headbang)(Headbang)(Headbang)