A cyclist and a jogger leave at the same time from the same spot and travel the same path. The cyclist rides 6 mph faster than the jogger runs. It takes the jogger 2 hrs to do the same distance as the cyclist does in 1 hr. find the speed of each.
I drew my box and did the operation D=R * T and came up with
6(R+1) = 2(R)
coming up with a final answer of R = -2
Can you tell me if I did this right? Thanks so much!!