If a ball were thrown horizontally with a velocity of 101.0 mi/h, how far would it fall vertically by the time it reached the ground, 60.5 ft away?
$\displaystyle t = \frac{\Delta x}{v_x}$
calculate t ... recommend you change mph to ft/sec
$\displaystyle \Delta y = v_{y0}t - \frac{1}{2}gt^2$
since $\displaystyle v_{y0}=0$ ...
$\displaystyle \Delta y = -\frac{1}{2}gt^2$
using $\displaystyle t$ calculated above, calculate $\displaystyle \Delta y$
note that $\displaystyle g = 32 \frac{ft}{s^2}$