...Could someone please double check this for me and see if I am doing it correctly.
Here is what the equation is and I'm supposed to find is the center point for (x,y) and the radius of the circle.
2x^2 + 2y^2 + 20x +16y + 10 =0
2x^2 + 2y^2 +20x + 16y = -10
2x^2/2 + 2y^2/2 +20x/2 + 16y/2 = -10/2
x^2 + y^2 + 10x + 8y = -5
(x^2+10x+25) + (y^2 + 8y + 16) = -5 + 25 + 16
(x+5)^2 + (y+4)^2 = 36 = 6^2
Which yields my answer of ....
(-5, -4) with a radius of 6. Don't miss the negative signs!
Please let me know if I am doing these correctly... I have no way to check my answer thus no way to know if i am on the right path.