We just started doing inequalities in class and I get the basics, but this is what gets me.
M = 7, point (0,-5)
How would I write this in Y = mx + b format?
$\displaystyle y = m * x + b$
First, we know m:
$\displaystyle y = 7 * x + b$
Next, we know x and y:
$\displaystyle -5 = 7 * 0 + b$
Solve for b:
$\displaystyle -5 = b$
Notice, if $\displaystyle x = 0$, and $\displaystyle (x,y)$ is on the line, $\displaystyle b = y$.
So, now, write your equation down:
$\displaystyle y = 7 * x + -5$
Or:
$\displaystyle y = 7 * x - 5$
$\displaystyle y = m * x + b$
First, we know m:
$\displaystyle y = \frac 3 2 * x + b$
Next, we know x and y:
$\displaystyle -6 = \frac 3 2 * 5 + b$
Solve for b:
$\displaystyle -6 - \frac {15} 2 = \frac {-27} 2 = b$
So, now, write your equation down:
$\displaystyle y = \frac 3 2 * x + \frac {-27} 2$
Find the slope:
$\displaystyle m=\frac{y_1-y_2}{x_2-x_1}=\frac{8-2}{0-4}=\frac{6}{-4}=-\frac{3}{2}$
From (0, 8) we know the y-intersept = 8.
Use the slope-intercept form of the general equation:
$\displaystyle y=mx+b$, where m is the slope, and b is the y-intercept.
$\displaystyle y=-\frac{3}{2}x+8$