find the equation of the perpendicular bisector of (2,-5) and (6,9), expressing your answer in the form: ax + by + c = 0
thanks for any help i can quite seem to get this one...
and its in for tomorrow!! gah!
Find the midpoint of the line segment through (2, -5) and (6, 9):
Find the slope of the line through (2, -5) and (6, 9).
slope =
The slope of the perpendicular bisector is the negative reciprocal of that slope, so it would be and pass through the midpoint (4, 2).
Using y=mx+b and m = through (4, 2).
Hello, pop_91!
All the necessary information is there ... just dig it up.
Find the equation of the perpendicular bisector of and
expressing your answer in the form:
The perpendicular bisector of goes through the midpoint of
. . and is perpendicular to
The midpoint of is: .
The slope of is: .
The perpendicular slope is: .
The line through with slope is:
. .
Multiply by 7: .
. . Therefore: .