find the equation of the perpendicular bisector of (2,-5) and (6,9), expressing your answer in the form: ax + by + c = 0

thanks for any help i can quite seem to get this one...

and its in for tomorrow!! gah!

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- Oct 6th 2008, 09:42 AMpop_91perpenicular bisector...?
find the equation of the perpendicular bisector of (2,-5) and (6,9), expressing your answer in the form: ax + by + c = 0

thanks for any help i can quite seem to get this one...

and its in for tomorrow!! gah! - Oct 6th 2008, 10:01 AMmasters
Find the midpoint of the line segment through (2, -5) and (6, 9):

Find the slope of the line through (2, -5) and (6, 9).

slope =

The slope of the perpendicular bisector is the negative reciprocal of that slope, so it would be and pass through the midpoint (4, 2).

Using y=mx+b and m = through (4, 2).

- Oct 6th 2008, 10:03 AMpop_91
thank you soo much!!!! (Rofl)

- Oct 6th 2008, 10:03 AMSoroban
Hello, pop_91!

All the necessary information is there ... just dig it up.

Quote:

Find the equation of the perpendicular bisector of and

expressing your answer in the form:

The perpendicular bisector of goes through the midpoint of

. . and is perpendicular to

The midpoint of is: .

The slope of is: .

The perpendicular slope is: .

The line through with slope is:

. .

Multiply by 7: .

. . Therefore: .