f(x)=3/x-1;g(x)=2/x i don't get how this works..
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Originally Posted by FinalFantasy9291 f(x)=3/x-1;g(x)=2/x i don't get how this works.. Is $\displaystyle f(x)= \frac{3}{x-1}$ or $\displaystyle \frac{3}{x}-1 $ ???
the first one
$\displaystyle f\circ g(x)= \frac{3}{\frac{2}{x}-1}=\frac{3x}{2}-3$ So it can accept any real or complex argument
Originally Posted by Greengoblin $\displaystyle f\circ g(x)= \frac{3}{\frac{2}{x}-1}=\frac{3x}{2}-3$ So it can accept any real or complex argument Correction: $\displaystyle \frac{3}{\frac{2}{x}-1}= \frac{3x}{2 - x}$.
Ooops my mistake, so the domain is $\displaystyle \{x\in\mathbb{R}:x\ne 2\}$ that certainly makes more sense.
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