If P = (-3, 1) and Q = (x, 4), find all numbers x such that the vector represented by line PQ has length 5.

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- Oct 4th 2008, 03:07 AMmagentaritaFind All Numbers x
If P = (-3, 1) and Q = (x, 4), find all numbers x such that the vector represented by line PQ has length 5.

- Oct 4th 2008, 04:10 AMearboth
1. Calculate the vector $\displaystyle \overrightarrow{PQ} = \overrightarrow{OQ} - \overrightarrow{OP} = ((x-(-3)), 3)$

2. Calculate the magnitude of the vector $\displaystyle \overrightarrow{PQ}$ which has to be 5:

$\displaystyle \sqrt{(x+3)^2+3^2} = 5$ Square both sides:

$\displaystyle (x^2+6x+9) +9 = 25~\implies~x^2+6x-7=0~\implies~x=-7~\vee~x=1$

3. Therefore $\displaystyle Q_1 (-7,4)$ or $\displaystyle Q_2(1,4)$ - Oct 4th 2008, 04:55 AMmagentaritagreat work.......
- Oct 4th 2008, 09:07 AMbkarpuz
Note that $\displaystyle Q\in\mathcal{C}$, where $\displaystyle \mathcal{C}$ is the circle centered at $\displaystyle P$ with the radius $\displaystyle r=5$.

Just write the equation of $\displaystyle \mathcal{C}$ and substitute $\displaystyle Q$ to this equation and solve $\displaystyle x$ as**earboth**done.

(Wink)