This is just some hw question I'm stuck on ³√(x³+7) = (x+1) and (3x – 2)^5/6 = 2
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Originally Posted by civiliam This is just some hw question I'm stuck on ³√(x³+7) = (x+1) and (3x – 2)^5/6 = 2 Cube both sides:
Hello, civiliam! Raise both sides to the power . . . . . . . . . . . . . . . . . . . . . . . . . . . .
thank you both I think I need to review exponents
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