Hello, fabxx!
That is a terrible graph!
. . And not a "neat" problem either . . .
Code:

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The quadratic function is a downopening parabola.
Its maximum (vertex) is at: .(2, h(2))
If , we are seeking the xintercepts of the graph.
One is to the left of the origin (negative)
. . the other is to the right of
We know that the two intercepts are symmetric
. . about the axis of symmetry,
Since the left intercept is negative, it is more than 2 units to the left of
Then the right intercept is more than 2 units to the right of
. . Hence: .
Among the given choices, the only one is: . . . . answer (a)