how do i figure where this equation passes through the orgin

1/x^2+8x+16

Printable View

- Sep 30th 2008, 08:54 PMvinson24passing through orgin
how do i figure where this equation passes through the orgin

1/x^2+8x+16 - Sep 30th 2008, 09:00 PMJameson
Well the origin is always (0,0) so any graph that passes it has to go through that point!

Maybe you read the question incorrectly. - Sep 30th 2008, 09:02 PMvinson24
the question originally asked for all values of x which the tangent line to that equation passes through the orgin

- Sep 30th 2008, 10:49 PMmr fantastic
It always helps to know the original question, rather than a (wrong) interpretation of the original question.

The tangent to the curve y = 1/x^2+8x+16 passing through the origin is very different to y = 1/x^2+8x+16 passing through the origin. Even though y = 1/x^2+8x+16 is completely ambiguous (is it 1/(x^2+8x+16) or (1/x^2) + 8x + 16 .....?) none of the possible interpretations of the equation of your curve pass through the origin.

Please be clearer what the equation of the curve is.