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Thread: help me find the inverse function please

  1. September 30th 2008, 07:40 AM #1
    kudies
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    help me find the inverse function please

    f(x)=3x+4
    2x-3



    (three x plus four divided by two x minus three)

    and


    f(x)= x^2+3 where x>0
    3x^2
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  2. September 30th 2008, 07:58 AM #2
    bobak
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    Quote Originally Posted by kudies View Post

    f(x)= \frac{3x+4}{2x-3}
    2xf(x) - 3f(x) = 3x+4

    x ( 2f(x) - 3) = 3f(x)+4

    x = \frac{3f(x)+4}{2f(x) - 3}

    \therefore f^{-1} (x) = \frac{3x+4}{2x - 3}

    Can you do the next one ?

    Bobak
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