Thread: help me find the inverse function please

1. help me find the inverse function please

f(x)=3x+4
2x-3

(three x plus four divided by two x minus three)

and

f(x)= x^2+3 where x>0
3x^2

2. Originally Posted by kudies

$f(x)= \frac{3x+4}{2x-3}$
$2xf(x) - 3f(x) = 3x+4$

$x ( 2f(x) - 3) = 3f(x)+4$

$x = \frac{3f(x)+4}{2f(x) - 3}$

$\therefore f^{-1} (x) = \frac{3x+4}{2x - 3}$

Can you do the next one ?

Bobak