How do I find Cx CD = sq. root{ [(sq. root (16 - (Cx-1)^2) + 2] - Cy }^2 Cx is supposed to equal + or - [sq. root (16- (CD+1)^2 ] +1
Follow Math Help Forum on Facebook and Google+
CD, Cx, Cy ... what do these mean?
CD is a length Cx is the x coordinate of C and Cy is the y coordinate of C I just need help how to get Cx outta there....
CD = sq. root{ [(sq. root (16 - (Cx-1)^2) + 2] - Cy }^2 I can't interpret your syntax ... how did you determine this for segment CD? It might help to know what the original problem statement says in its entirety.
Create a rule that allows you to predict the location of C when you know the length of CD, Ignore the sentence to the right, that was a different problem involving the circle...
point D is on the circle. the coordinates for point D are point C has coordinates CD is the vertical distance between D and C ... the difference between the y-values.
View Tag Cloud