1. ## Range and Domain

I need a little help here-not sure if I got it right:
f(x)= 2/x+1, g(x)= x/x+1
domain of f is {x is part of a set where x >0} and domain of g is {x is part of a set where x is greater than or equal to 0} [0, infinity)U(0,infinity).

2. OK

Both of the functions are rational functions... in other words, of the form

$\displaystyle f(x) = \frac{g(x)}{h(x)}$, where $\displaystyle g(x)$ and $\displaystyle h(x)$ are continuous functions of $\displaystyle x$.

$\displaystyle f(x)$ is also continuous at all points except where the denominator $\displaystyle (h(x))=0$.

So where does the denominator equal 0? In both cases, where $\displaystyle x = -1$.

So the domain of each function is $\displaystyle \mathbf{R}\backslash \{-1\}$.

3. ## Range and domain

The first one...

4. Sorry for the double post, didn't realise I edited the first one instead of adding a new one.

OK

Both of the functions are rational functions... in other words, of the form

, where and are continuous functions of .

is also continuous at all points except where the denominator .

So where does the denominator equal 0? In both cases, where .

So the domain of each function is $\displaystyle \mathbf{R} \backslash \{-1\}$.

5. ## range and domain

wow..so i wasn't even close, huh?

6. Originally Posted by Vivianp
wow..so i wasn't even close, huh?
No, but that's ok, that's what we're here for.

Just always have in the back of your mind "You can't divide by 0" and you'll be fine