I need a little help here-not sure if I got it right:
f(x)= 2/x+1, g(x)= x/x+1
domain of f is {x is part of a set where x >0} and domain of g is {x is part of a set where x is greater than or equal to 0} [0, infinity)U(0,infinity).
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I need a little help here-not sure if I got it right:
f(x)= 2/x+1, g(x)= x/x+1
domain of f is {x is part of a set where x >0} and domain of g is {x is part of a set where x is greater than or equal to 0} [0, infinity)U(0,infinity).
OK
Both of the functions are rational functions... in other words, of the form
, where
and
are continuous functions of
.
is also continuous at all points except where the denominator
.
So where does the denominator equal 0? In both cases, where.
So the domain of each function is.
The first one...
Sorry for the double post, didn't realise I edited the first one instead of adding a new one.
OK
Both of the functions are rational functions... in other words, of the form
http://www.mathhelpforum.com/math-he...518d3190-1.gif, where http://www.mathhelpforum.com/math-he...482c35c3-1.gif and http://www.mathhelpforum.com/math-he...e8ba0833-1.gif are continuous functions of http://www.mathhelpforum.com/math-he...155c67a6-1.gif.
http://www.mathhelpforum.com/math-he...a378be62-1.gif is also continuous at all points except where the denominator http://www.mathhelpforum.com/math-he...1881b207-1.gif.
So where does the denominator equal 0? In both cases, where http://www.mathhelpforum.com/math-he...16e275fc-1.gif.
So the domain of each function is.
wow..so i wasn't even close, huh?
No, but that's ok, that's what we're here for.Quote:
Originally Posted by Vivianp
Just always have in the back of your mind "You can't divide by 0" and you'll be fine (Happy)