Find the center and the radius of the circle x^2 + y^2 - 2ax + 4by = 0.
Does every equation of the form x^2 + mx + y^2 + ny = p represent a circle? Explain.
Complete the square on x and y and gather terms into something like:
(x+p)^2 + (y+q)^2 = r^2
Then (-p, -q) is the centre and r is the radius.
It's not a circle if r^2 = 0 in which case it's a single point.
Or when r^2 is negative in which case there are no points at all.