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Math Help - Election Day

  1. #1
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    Election Day

    In a town election, candidates A and B were running for mayor. There were 30,500 people eligible to vote, and 3/4 of them actually voted.Candidate B received 1/3 of the votes cast. How many people voted forcandidate B? What percent of the votes cast, to the nearest tenth of a percent, did candidate A receive?

    My work:

    3/4 times 30,500 = 22875

    1/3 times 22,875 = 7548.75

    2/3 of the people voted for Candidate A

    Of course, I'm wrong.

    Help!
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  2. #2
    Like a stone-audioslave ADARSH's Avatar
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    Hello,

    1/3 times 22,875 = 7548.75

    check it once again
    humans can't b in decimals
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  3. #3
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    Smile sorry

    Quote Originally Posted by ADARSH View Post
    Hello,

    1/3 times 22,875 = 7548.75

    check it once again
    humans can't b in decimals
    Sorry....1/3 times 22,875 = 7625

    If 1/3 represents the votes for B, then the votes for A should be 3/3 - 1/3 = 2/3 = 0.666666667

    What percent of the votes cast, to the nearest tenth of a percent, did candidate A receive?

    The correct answer is 66.7%.

    How does 0.666666667 become 66.6%?

    Thanks
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  4. #4
    Like a stone-audioslave ADARSH's Avatar
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    Smile ....

    Hello,
    What percent of the votes cast, to the nearest tenth of a percent, did candidate A receive?

    The correct answer is 66.7%.

    Here the percent signifies that

    If there are 100 votes cast
    how many would A get ?
    u know that A has 2/3 of total votes cast
    so u need (2/3) of 100

    ie; 2*100/3 = 66.7 %<------shows per 100(per-cent)
    if u still find trouble let me know it
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  5. #5
    A riddle wrapped in an enigma
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    Quote Originally Posted by magentarita View Post
    Sorry....1/3 times 22,875 = 7625

    If 1/3 represents the votes for B, then the votes for A should be 3/3 - 1/3 = 2/3 = 0.666666667

    What percent of the votes cast, to the nearest tenth of a percent, did candidate A receive?

    The correct answer is 66.7%.

    How does 0.666666667 become 66.6%?

    Thanks
    It doesn't.

    \frac{3}{4} \times 30500 = 22875 voted.

    Of those,

    \frac{1}{3} \times 22875 = 7625 voted for candidate B.

    \frac{3}{3}-\frac{1}{3}=\frac{2}{3} \times 22875=15250 voted for candidate A.

    \frac{2}{3}=\overline{.6}=.666666666 \hdots \approx .7

    \frac{2}{3} = 66 \frac{2}{3} \% \approx 66.7 \%
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