Thread: Election Day

In a town election, candidates A and B were running for mayor. There were 30,500 people eligible to vote, and 3/4 of them actually voted.Candidate B received 1/3 of the votes cast. How many people voted forcandidate B? What percent of the votes cast, to the nearest tenth of a percent, did candidate A receive?

My work:

3/4 times 30,500 = 22875

1/3 times 22,875 = 7548.75

2/3 of the people voted for Candidate A

Of course, I'm wrong.

Help!

Hello,

1/3 times 22,875 = 7548.75

check it once again
humans can't b in decimals

Originally Posted by ADARSH

Hello,

1/3 times 22,875 = 7548.75

check it once again
humans can't b in decimals

Sorry....1/3 times 22,875 = 7625

If 1/3 represents the votes for B, then the votes for A should be 3/3 - 1/3 = 2/3 = 0.666666667

What percent of the votes cast, to the nearest tenth of a percent, did candidate A receive?

The correct answer is 66.7%.

How does 0.666666667 become 66.6%?

Thanks

Hello,
What percent of the votes cast, to the nearest tenth of a percent, did candidate A receive?

The correct answer is 66.7%.

Here the percent signifies that

If there are 100 votes cast
how many would A get ?
u know that A has 2/3 of total votes cast
so u need (2/3) of 100

ie; 2*100/3 = 66.7 %<------shows per 100(per-cent)
if u still find trouble let me know it

Originally Posted by magentarita

Sorry....1/3 times 22,875 = 7625

If 1/3 represents the votes for B, then the votes for A should be 3/3 - 1/3 = 2/3 = 0.666666667

What percent of the votes cast, to the nearest tenth of a percent, did candidate A receive?

The correct answer is 66.7%.

How does 0.666666667 become 66.6%?

Thanks

It doesn't.

voted.

Of those,

voted for candidate B.

voted for candidate A.