1. ## Election Day

In a town election, candidates A and B were running for mayor. There were 30,500 people eligible to vote, and 3/4 of them actually voted.Candidate B received 1/3 of the votes cast. How many people voted forcandidate B? What percent of the votes cast, to the nearest tenth of a percent, did candidate A receive?

My work:

3/4 times 30,500 = 22875

1/3 times 22,875 = 7548.75

2/3 of the people voted for Candidate A

Of course, I'm wrong.

Help!

2. Hello,

1/3 times 22,875 = 7548.75

check it once again
humans can't b in decimals

3. ## sorry

Hello,

1/3 times 22,875 = 7548.75

check it once again
humans can't b in decimals
Sorry....1/3 times 22,875 = 7625

If 1/3 represents the votes for B, then the votes for A should be 3/3 - 1/3 = 2/3 = 0.666666667

What percent of the votes cast, to the nearest tenth of a percent, did candidate A receive?

How does 0.666666667 become 66.6%?

Thanks

4. ## ....

Hello,
What percent of the votes cast, to the nearest tenth of a percent, did candidate A receive?

Here the percent signifies that

If there are 100 votes cast
how many would A get ?
u know that A has 2/3 of total votes cast
so u need (2/3) of 100

ie; 2*100/3 = 66.7 %<------shows per 100(per-cent)
if u still find trouble let me know it

5. Originally Posted by magentarita
Sorry....1/3 times 22,875 = 7625

If 1/3 represents the votes for B, then the votes for A should be 3/3 - 1/3 = 2/3 = 0.666666667

What percent of the votes cast, to the nearest tenth of a percent, did candidate A receive?

How does 0.666666667 become 66.6%?

Thanks
It doesn't.

$\displaystyle \frac{3}{4} \times 30500 = 22875$ voted.

Of those,

$\displaystyle \frac{1}{3} \times 22875 = 7625$ voted for candidate B.

$\displaystyle \frac{3}{3}-\frac{1}{3}=\frac{2}{3} \times 22875=15250$ voted for candidate A.

$\displaystyle \frac{2}{3}=\overline{.6}=.666666666 \hdots \approx .7$

$\displaystyle \frac{2}{3} = 66 \frac{2}{3} \% \approx 66.7 \%$