Solve equation for x 0 - 360 (degrees) 4sinx + 3cosx = 6
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Originally Posted by gracey Solve equation for x 0 - 360 (degrees) 4sinx + 3cosx = 6 write $\displaystyle 4 \sin x = 6 - 3 \cos x$ now square both sides. what do you get? can you continue? think quadratic equation (note you will need to use a famous trig identity before you can get it into quadratic form. try to change all the sines into cosines)
There are no values of x that satisfy the equation. You can use Rcos(x-Q)=4sinx + 3cosx, RcosxcosQ+RsinxsinQ = 4sinx + 3cosx RcosQ=3 RsinQ=4 tanQ=4/3 R=5 5cos(x-Q) =6 ... (1) Equation 1 does not have have solutions.
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