Thread: graph of y=e^2x

how does the graph of

I have tried it using a math software but it shows a straight line with 0 as the y - intercept which seems wrong to me as

I would be delighted if you can show me the graph of it and is there any asymptote? is the asymptote y = 0? , let x = -n , where n is an integer , , the y will be getting closer and closer to 0 but will never reach it

did you graph

y = e^2x

or

y = e^(2x)

?

You probably graphed ax where a is e^2 instead of e^(2x). I attached the graph of .

And e^{2x} approaches 0 as x approaches negative infinity.

Originally Posted by skeeter

did you graph

y = e^2x

or

y = e^(2x)

?

sry it is y=e^(2x)

Originally Posted by Chop Suey

You probably graphed ax where a is e^2 instead of e^(2x). I attached the graph of .

And e^{2x} approaches 0 as x approaches negative infinity.

Thanks a lot!